For a dipole q=2×10^–6C and d = 0.01m. Calculate the maximum torque for this dipole if E = 5×10⁵N/C.

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1×10^–3Nm

10×10^–3Nm

1×10²Nm

10×10^–2Nm

answer is B.

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Detailed Solution

$\begin{array}{l} max. Torque = PE = q \times a \times E \\ = 2 \times 10^{- 6} \times 10^{- 2} \times 5 \times 10^{5} = 10 \times 10^{- 3} \end{array}$

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