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For a first order reaction, if the time taken for completion of 50% of the reaction is ‘t’ seconds, the time required for completion of 99.9% of the reaction is:

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10t

100t

answer is A.

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Detailed Solution

$For 1^{st} order reaction t_{99.9 %} = 10 \times t_{1 / 2}$
= 10t sec.

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