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For a first order reaction $t_{0.75}$ is 138.6 sec. Its specific rate constant is (in $s^{- 1}$ )

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$10^{- 2}$

$10^{- 4}$

$10^{- 5}$

$10^{- 6}$

answer is A.

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Detailed Solution

k= $\frac{2.303}{t} \times \log (\frac{C_{0}}{C_{t}})$

$k = \frac{2.303}{138.6} \times \log (\frac{100}{25})$

k= $10^{- 2}$

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