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Q.

For a first order reaction, the time required for completion of 90% reaction is 'x' times the half life of the reaction. The value of 'x' is (Given: ln 10 = 2.303 and log 2 = 0.3010)

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a

2.43

b

1.12

c

3.32

d

33.31

answer is C.

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Detailed Solution

 Given t0.90=xt1/2  First order rate constant  K=ln2t1/2=1xt1/2lnA0A0A0×90100 ln2t1/2=ln10xt1/2x=ln10ln2=2.3032.303×0.3010=3.32

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