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Q.

For a first order reaction, the time required for completion of 90% reaction is ‘x’ times the half life of the reaction. The value of ‘x’ is

(Given: in 10=2.303 and log2=0.3010)

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a

3.32

b

2.43

c

1.12

d

33.31

answer is C.

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Detailed Solution

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t0.90=Xt1/2

First order rate constant,

K=ln2t1/2=1xt1/2lnA0A0−A0×90100

ln2t1/2=ln10xt1/2⇒ln10ln2=2.3032.303×0.3010=3.32

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