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Q.

For a gas having molar mass M, specific heat at constant pressure can be given as:

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a

$\frac{γR}{M (γ - 1)}$

b

$\frac{γ}{RM}$

c

$\frac{M}{R (γ - 1)}$

d

$\frac{γRM}{γ + 1}$

answer is A.

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Detailed Solution

detailed_solution_thumbnail

$C_{p} = \frac{γR}{γ - 1} \to 1$ mole M gms

$? \to 1 gm$

Specific heat $= \frac{γR}{(γ - 1) M}$

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