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For a gaseous reaction , $2 A ⟶ 3 B + 5 C$ occurring at constant temperature and volume, pressure at different instants were observed. What will be the half life of' A' at a pressure of 20 atm?
t 0 10 min 15 min
Total Pressure 10 atm 16 atm 19 atm

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2 min

50 min

20 min

40 min

answer is A.

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Detailed Solution

we have

$2 A ⟶ 3 B + 5 C$

$t = 0 10 - -$

$t = t 10 - x \frac{3 x}{2} \frac{5 x}{2}$

Total

$P = 10 + 3 x = 16 \Rightarrow x = 2$

$10 + 3 x = 19 \Rightarrow x = 3$

$\Rightarrow R x^{n} follows$

Zero order kinetics

$k = \frac{2}{10}$

$t_{1 / 2} = \frac{a}{2 k} = \frac{20 \times 10}{2 \times 2} = 50 \min$

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