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For a gaseous reaction : $2 A (g) ⟶ 3 B (g) + 4 C (g)$ occurring in a rigid vessel, if initially pressure is 3 atm and after 10 minutes and 20 minutes the pressure is 6. 75 atm and 10.5 atm respectively, then what will be the order of reaction?

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$\frac{1}{2}$

answer is A.

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Detailed Solution

$2 A ⟶ 3 B + 4 C$

$\begin{array}{l} \begin{array}{cccc} t = 0 & 3 & - & - \\ t = t & 3 - x & \frac{3 x}{2} & 2 x \end{array} \\ P_{T} = 3 + \frac{5 x}{2} \end{array}$

At t = 10 min, x = 1.6

At t = 20 min, x = 3.0

$R x^{n}$ goes to completion and follows x = kt

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