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Q.

For a given chemical reaction A→B at 300K the free energy change is  −49.4 kJ mol−1 and the enthalpy of reaction is 51.4 kJmol−1 . The entropy change of the reaction is ______ JK−1mol−1.

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answer is 336.

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Detailed Solution

Given chemical reaction;
 A→BΔG=−49.4kJ/mol
 ΔH=51.4kJ/mol;ΔS=?
 ⇒ From the relations ΔG=ΔH−TΔS
 ⇒ΔS=ΔH−ΔGT=[51.4−(49.4)]×10003001mol K
 ⇒ΔS=336JK−1mol−1

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