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Q.

For a given chemical reaction A B at 300 K the free energy change is – 49.4 kJ mol-1 and the enthalpy of reaction is 51.4 5 kJ mol-1. The entropy change of the reaction is ____ kJ mol-1.

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a

0.336

b

0.348

c

0.486

d

0.548

answer is A.

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Detailed Solution

The formula to calculate entropy change is

                 ΔG=ΔH-TΔS

 Given, T=300; ΔG=-49.4; ΔH=51.45; on substituting all values

 -49.4=51.45-300ΔS

 ΔS=100.85300=0.336 kJ/mol or 336 J/mol.

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