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For a given chemical reaction $A \to B$ at 300 K the free energy change is $- 49.4 k J m o l^{- 1}$ and the enthalpy of reaction is $51.4 k J K^{- 1} m o l^{- 1}$ . The entropy change of the reaction is $J K^{- 1} m o l^{- 1} .______$

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answer is 336.

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Detailed Solution

From,

$Δ H = Δ G + T Δ S ∴ Δ S = \frac{Δ H - Δ G}{T}$

$∴ Δ S = [\frac{51.4 - (- 49.4)}{300}] \times 1000 J K^{- 1} m o l^{- 1} = 336 J K^{- 1} m o l^{- 1}$

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