For a given gas at 1 atm pressure, rms speed of the molecules is 200 m/s at 127∘C. At 2 atm pressure and at 227∘C, the rms speed of the molecules will be

T1= 127∘C = 400 K and T2= 227∘C = 500 KSince vrms=3RTm⇒vrms∝Tvrms1vrms2=T1T2⇒vrms2=1005 m/s

For a given gas at 1 atm pressure, rms speed of the molecules is 200 m/s at 127∘C. At 2 atm pressure and at 227∘C, the rms speed of the molecules will be

T1= 127∘C = 400 K and T2= 227∘C = 500 KSince vrms=3RTm⇒vrms∝Tvrms1vrms2=T1T2⇒vrms2=1005 m/s

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For a given gas at $1 atm$ pressure, $r m s$ speed of the molecules is $200 m / s$ at $127^{\circ} C$ . At $2 a t m$ pressure and at $227^{\circ} C$ , the rms speed of the molecules will be

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$80 \sqrt{3} m / s$

$100 \sqrt{5} m / s$

$80 m / s$

$100 m / s$

answer is B.

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$T_{1} = 127^{\circ} C = 400 K and T_{2} = 227^{\circ} C = 500 K$

Since $v_{rms} = \sqrt{\frac{3 RT}{m}} \Rightarrow v_{rms} \propto \sqrt{T}$

$\frac{v_{{rms}_{1}}}{v_{{rms}_{2}}} = \sqrt{\frac{T_{1}}{T_{2}}} \Rightarrow v_{{rms}_{2}} = 100 \sqrt{5} m / s$

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For a given gas at 1 atm pressure, rms speed of the molecules is 200 m/s at 127∘C. At 2 atm pressure and at 227∘C, the rms speed of the molecules will be

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For a given gas at $1 atm$ pressure, $r m s$ speed of the molecules is $200 m / s$ at $127^{\circ} C$ . At $2 a t m$ pressure and at $227^{\circ} C$ , the rms speed of the molecules will be