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Q.

For a given mass of a gas at constant temperature, the volume and the pressure are V and P respectively. Then the slope of the graph drawn between $\log_{e} V$ on X-axis and $\log_{e} P$ on Y-axis is

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a

1

b

-1

c

Infinity

d

Zero

answer is B.

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Detailed Solution

$\begin{array}{l} PV = nRT \\ \log PV = \log nRT \end{array}$

$\begin{array}{l} \log P + \log V = \log (nRT) \\ \log P = (- 1) \log V + \log (nRT) \end{array}$

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