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Q.

For a given reaction, energy of activation for forward reaction Eaf is 80kJmol1ΔH=40kJ mol1 for the reaction. A catalyst lowers Eaf to 20kJ mol1 The ratio of energy of activation for reverse reaction before and after addition of catalyst is : 

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a

1.2

b

1.0

c

2.0

d

0.5

answer is D.

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Detailed Solution

EafEab=ΔH Eab=120kJ

After addition of catalyst,

Eab=12060=60kJ  Ratio =12060=21

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