For a given reaction of first order, it takes 20 minutes for the concentration to drop from $1 .0 mol {litre}^{- 1}$ to $0 .6 mol {litre}^{- 1}$ . The time required for the concentration to drop from $0 .6 mol {litre}^{- 1}$ to $0 .36 mol {litre}^{- 1}$ will be

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.

An Intiative by Sri Chaitanya

more than 20 minutes

less than 20 minutes

equal to 20 minutes

infinity

answer is C.

(Unlock A.I Detailed Solution for FREE)

JEE

NEET

Foundation JEE

Foundation NEET

CBSE

Detailed Solution

$\frac{2 .303}{20} \log \frac{1 .0}{0.6} = \frac{2 .303}{t} \log \frac{0 .6}{0.36}$

$∴$ $\frac{1}{20} \log 1.66 = \frac{1}{t} \log 1.66$

$∴ t = 20 minutes$

Watch 3-min video & get full concept clarity

No courses found

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test