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For a given reaction, $ΔH = 35 .5 kJ {mol}^{- 1}$ and $ΔS = 83 .6 J K^{- 1} {mol}^{- 1}$ . The reaction is spontaneous at (Assume that $ΔH and ΔS$ do not vary with temperature)

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T > 298 K

T > 425 K

All temperatures

T < 425 K

answer is A.

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Detailed Solution

For a spontaneous reaction, $ΔG < 0 i . e ., ΔH - TΔS < 0$
$T > \frac{ΔH}{ΔS}$
$T > (\frac{35 .5 \times 1000}{83 .6} = 425 K) = 425 K$
$∴ T > 425 K$

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