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For a given reaction $temperature coefficient, μ = 2$ .The temperature is increased from $40^{o} C to 60^{o} C$ .The correct relation between the rates of reactions $r_{1} (at 40^{o} C)$ and $r_{2}$ $(at 60^{o} C)$ is

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$r_{2} = 4 r_{1}$

$r_{1} = 4 r_{2}$

$r_{2} = 8 r_{1}$

$r_{2} = 81 r_{1}$

answer is A.

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Detailed Solution

$\frac{\frac{\overset{r_{1}}{40^{o} C} \overset{2 times}{\to} 50^{o} C \overset{2 times}{\to} \overset{r_{2}}{60^{o}} C}{4 times increased}}{}$

[OR]

$r_{2} = r_{1} {(μ)}^{\frac{∆ T}{10}} r_{2} = r_{1} \times 2^{2} r_{2} = 4 r_{1}$

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