For a homodiatomic molecule with a total number of electrons 14 , after filling $σ * 2$ s orbital the next electron goes to

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$π_{2 p y}$

$σ_{2 p z}$

$π_{2 p x} or π_{2 p y}$

$π_{2 p x}$

answer is D.

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Detailed Solution

In M.O.T the order of energy of '2' types of Molecular orbitals

$\Rightarrow σ_{1 s} < σ *_{1 s} < σ_{2 s} < σ *_{2 s} < π_{2 P_{x}} = π_{2 P_{y}} < σ_{2 P_{z}} < π_{2 P_{x}}^{*} = π_{2 P_{y}}^{*} < {σ^{*}}_{2 P_{z}}$

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