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The change in internal energy in a constant pressure process from temperature T₁ to T₂ is equal to
${nC}_{V} (T_{2} - T_{1})$ ,where C_v is the molar specific heat at constant volume and n is the number of mole of the gas.

The change in internal energy of the gas and the work done by the gas are equal in magnitude in an adiabatic process.

No heat is added or removed in an adiabatic process.

The internal energy does not change in an isothermal process.

answer is A, B, C, D.

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Detailed Solution

$(a) (b) (c) (d)$
$(a) △ U = n c_{v} △ t = n c_{v} (T_{1} - T_{2})$ for all process
(b) $△ Q = 0$ $△ U = - △ w | △ U | = | △ w |$

$(c) △ T = 0$ , $△ U = n c_{v} △ T = 0$

$(D) △ Q = 0$

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