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For a moving coil galvanometer, the deflection in the coil is $0.05 rad$ when a current of $10 mA$ is passed through it. If the torsional constant of suspension wire is $4.0 \times 10^{- 5} Nm {rad}^{- 1}$ , the magnitude field is $0.01 T$ and the number of turns in the coil is $200$ , the area of each turn ( $in {cm}^{2}$ ) is

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0.5

answer is B.

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Detailed Solution

$Cθ = BIAN$
$\begin{array}{l} 4 \times 10^{- 5} \times 0.05 = 0.01 \times 10 \times 10^{- 3} \times A \times 200 \\ A = 1.0 \times 10^{- 4} m^{2} \\ A = 1.0 {cm}^{2} \end{array}$

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