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For a normal eye, the cornea of eye provides a converging power of 40 D and the least converging power of the eye lens behind the cornea is 20 D. Using this information, the distance between the retina and the cornea-eye lens can be estimated to be

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a

1.67 cm

b

1.5 cm

c

5 cm

d

2.5 cm

answer is A.

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Detailed Solution

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The combination of cornea and eye lens forms eye system.
$∴$ The total power of two lenses would give the net power of the eye.
$P_{net} = P_{1} + P_{2} = (40 + 20) D = 60 D$
But power, $P = \frac{1}{F} (∴ F = \frac{1}{P} = \frac{1}{60} m) .$
$F = \frac{100}{60} c m = 1.67 c m$

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