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For a particle executing SHM. The KE ‘K’ is given by K = K0 cos2 wt. The maximum value of PE is

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a
K0
b
zero
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K02
d
K04

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detailed solution

Correct option is A

K.E=K0cos2ωt
But K.E=12mv2 x=Asinωt
V=Aωcosωt;  K.E=12mA2ω2cos2ωt compare with K.E=K0cos2ωtK0=122A2 max value of P.E  P.E Emax=12m2A2=k0

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