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For a particle executing SHM, the kinetic energy E is given by $E = E_{0} \cos^{2} ωt$ . The maximum value of the potential energy is

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$E_{0} / 4$

$E_{0}$

$E_{0} / 2$

$E_{0} / \sqrt{2}$

answer is A.

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$P E_{\max} = K E_{\max}$

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