For a particle starting from rest and travelling with a uniform acceleration along a straight line

$\left(i\right) v\infty t \left(ii\right) s\infty t^2 \left(iii\right) v\infty \sqrt{s}$

Given that a particle starting from rest u = 0

Moving with uniform acceleration 

Then we can have final velocity = v

After time taken = t

Distance covered = s

By using equation of motion

i) $$\begin{gathered} v=u+at \\ \Rightarrow v=at \therefore v\infty t \\ \left(ii\right) s=ut+\frac{1}{2}a{t}^2 \\ \Rightarrow s=\frac{1}{2}a{t}^2 \therefore s\infty t^2 \\ \left(iii\right) v^2-u^2=2as \\ \Rightarrow v^2=2as \therefore v\infty \sqrt{s} \\ So we get all are true. \end{gathered}$$