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For a particular electromagnetic radiation the following slopes are obtained when plotted as follows
x-axis y-axis slope
$γ$ (Frequency) E(energy) straight line with positive slope = S₁
$\frac{1}{λ}$ E straight line with positive slope = S₂
Ratio between S₂ to S₁ is equal to

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twice velocity of light

velocity of light

half of velocity of light

infinity

answer is A.

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Detailed Solution

E = h $γ$

slope(S₁) = h

E = $\frac{hc}{λ}$

slope(S₂) = hc

$\frac{S_{2}}{S_{1}} = \frac{hc}{h} = c$ (velocity of light)

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