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Q.

For a particular reaction, ΔH∘=−40kJ and ΔS∘= - 200 JK-1 mol-1. The reaction is 

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a

spontaneous at all temperatures

b

nonspontaneous at all temperatures

c

spontaneous at temperature below -73° C

d

spontaneous at temperature above -73° C

answer is D.

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Detailed Solution

ΔG∘=ΔH∘−TΔS∘

 When ΔG∘=0,T=ΔH∘ΔS∘=−40×103−200=200K

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