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Q.

For a particular reaction, $Δ H^{\circ} = - 40 kJ and Δ S^{\circ}$ = - 200 JK^-1 mol^-1. The reaction is

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a

spontaneous at all temperatures

b

nonspontaneous at all temperatures

c

spontaneous at temperature below -73° C

d

spontaneous at temperature above -73° C

answer is D.

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Detailed Solution

$Δ G^{\circ} = Δ H^{\circ} - T Δ S^{\circ}$

$When Δ G^{\circ} = 0, T = \frac{Δ H^{\circ}}{Δ S^{\circ}} = \frac{- 40 \times 10^{3}}{- 200} = 200 K$

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