For a particular reversible reaction at temperature $T,\mathrm{\Delta }H$ and $\mathrm{\Delta }S$ were found to be both positive. If $T_{\mathrm{e}}$ is the temperature at equilibrium, the reaction would be spontaneous when 

Since $\mathrm{\Delta }G=\mathrm{\Delta }H-T\mathrm{\Delta }G$, we have

Reactions at equilibrium:                               $\mathrm{\Delta }G=\mathrm{\Delta }H-T_{\mathrm{e}}\mathrm{\Delta }S=0$

For a reaction to be spontaneous:              $\mathrm{\Delta }G=\mathrm{\Delta }H-T\mathrm{\Delta }S<0$

$\mathrm{\Delta }G$ will be negative provided     $T>T_{\mathrm{e}}$ as both $\mathrm{\Delta }H$ and $\mathrm{\Delta }S$ are positive.