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For a particular reversible reaction at temperature T, $∆ H$ and $∆ S$ were found to be both positive. If $T_{e}$ is the temperature at equilibrium, the reaction would be spontaneous when

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T_e > T

T > T_e

T_e is 5 times T

T = T_e

answer is B.

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Detailed Solution

$Given, ∆ H = + ve, ∆ S = + ve; ∆ G = ∆ H - T ∆ S; ∆ G = + ve - T (+ ve); ∆ G becomes - ve only when T > T_{e}$

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