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Q.

For a perfect gas, two pressures $P_{1}$ and $P_{2}$ are shown in figure. The graph shows:

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a

Insufficient data to draw any conclusion

b

$P_{1} > P_{2}$

c

$P_{1} < P_{2}$

d

$P_{1} = P_{2}$

answer is A.

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Detailed Solution

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$\begin{array}{rcl} PV & = & nRT \\ \frac{V}{T} & = & \frac{nR}{P} \\ \frac{nR}{P_{1}} & < & \frac{nR}{P_{2}} \\ P_{2} & < & P_{1} \end{array}$

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For a perfect gas, two pressures P1 and P2 are shown in figure. The graph shows: