Q.

For a point P in the plane, let d1(P)and  d2(P) be the distances of the point P from the lines x – y = 0 and x + y = 0 respectively. The area of the region R consisting all the points P lying in the plane satisfying 4d1(P)+d2(P)8 is A square units. Then A32=

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answer is 3.

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Detailed Solution

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4|x+y2|+|xy2|8 Area A=(82)2(42)2=96

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For a point P in the plane, let d1 (P)and  d2 (P) be the distances of the point P from the lines x – y = 0 and x + y = 0 respectively. The area of the region R consisting all the points P lying in the plane satisfying 4 ≤ d1 (P)+ d2 (P)≤ 8 is A square units. Then A32=