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For a process value of ${TΔS}_{sys}$ is −40KJ/mole, then for the process to be spontaneous, ${ΔH}_{sys}$ must be

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−20 KJ/mole

+60KJ/mole

+50KJ/mole

−45KJ/mole

answer is D.

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Detailed Solution

$∆ G = ∆ H - T ∆ S$

$∆ G = ∆ H - (- 40)$

$∆ G_{sys}$ must be negative and $∆ H$ must be negative and magnitude must be higher than $T ∆ S$

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