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Q.

For a reaction : 2A(g)+B(g)⟶C(g),ΔU∘=30 kcal/mole,ΔS∘=100cal/K mole at 300K.  What will be the value of ΔGreaction ∘ at  400K ? [R=2cal/K mole ]ΔCPreaction =0.

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a

- 1.2 kcal

b

0

c

- 11.2 kcal

d

- 10 kcal

answer is C.

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Detailed Solution

In the reaction we have,

2A(g)+B(g)⟶C(g),ΔU∘=30kcal/moleΔH∘=ΔU∘+ΔngRT =30+(−2)×2×3001000=28.8kcal/moleΔG∘=ΔH∘−TΔS∘ =28.8−400×1001000=−11.2kcal/mole
 

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