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Q.

For a reaction $A + B \to C + D$ $AH = - 30 kJ$ ${mole}^{- 1} .$ the activation energy for the forward reaction is 65kJ ${mole}^{- 1} .$ the activation energy for the backward reaction is

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answer is 95.

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Detailed Solution

$\begin{array}{l} Δ H = E_{a} - {E_{a}}^{1} \\ - 30 = 65 - {E_{a}}^{1} \Rightarrow {E_{a}}^{1} = 95 \end{array}$

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