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Q.

For a reaction, consider the plot of  ln K  versus  1/T  given in the figure if the rate constant of this reaction at 400K is 10-5 S-1, then the rate constant at 500K is:
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a

106  s1

b

4×104  s2

c

104  s1

d

2×104s1

answer is C.

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Detailed Solution

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 From Arrhenius equation
 In K =lnAEaRT
Slope = EaRT=4606K
log[k2k1]=Ea2.303R[1T1T2]

log[k2105]=12.303×4606[14001500]
=4606×1002.303×400×500=1
log[k2105]=1;k2105=Antilog  (1)

k2105=10    k2=105×10  =104  s1

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