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Q.

For a reaction, given below is the graph of 1n k vs 1T. The activation energy for the reaction is equal to ____________ cal mol-1. (Nearest integer). 

(Given: R = 2 cal K-1 mol-1)

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answer is 8.

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Detailed Solution

K = Ae-EA/RT ln k = -EaR = 205 Ea = 4R = 8 Cal/mol

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