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Q.

For a reaction R1 , \large \Delta G\,=\,x\,\,KJ\,\,mo{{l}^{-1}}. For a reaction R2 , \large \Delta G\,=\,y\,\,KJ\,\,mo{{l}^{-1}}.

Reaction R1 is non-spontaneous but along with R2 it is spontaneous. This means that

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a

x is +ve, y is -ve but in magnitude y > x

b

Both x and y are +ve but not equal.

c

Both x and y are -ve but not equal

d

x is -ve , y is +ve but in magnitude x > y

answer is B.

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Detailed Solution

A process is non spontaneous means G=+ve ;

Thus for R1, G=x=+ve; But for R2 G=y=-ve because it is spontaneous; R1 becomes spontaneous in presence of R2, this is possible only when magnitude of y>x ;

 

Such reactions are known as coupling reactions.

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For a reaction R1 , For a reaction R2 , Reaction R1 is non-spontaneous but along with R2 it is spontaneous. This means that