For a reaction scheme $A \overset{K_{1}}{\to} B \overset{K_{2}}{\to} C$ if the Rate of formation of B is set to be zero then the concentration of B given by

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$K_{1} K_{2} [A]$

$\frac{K_{1} (A)}{K_{2}}$

$(K_{2} - K_{1}) (A)$

$(K_{1} + K_{2}) [A]$

answer is B.

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Detailed Solution

$\begin{array}{l} A \overset{K_{1}}{\to} B \overset{K_{2}}{\to} C \\ \frac{d (B)}{dt} = K_{1} (A) - K_{2} (B) = 0 \\ K_{1} (A) = K_{2} (B) \\ [B] = \frac{K_{1}}{K_{2}} [A] \end{array}$

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