Q.

For a reaction, the graph drawn between t1/2 and ‘a’ gives a straight line passing through the origin with the slope 2 × 102 mole–1.lit.min. If the initial concentration of the reactant is 1M, then the half life period is ____ × 102 min.

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answer is 2.

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Detailed Solution

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t12=C02×Kt12=12K×C0t12=1×4×1022×1;t12=4×1022=2×102

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