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For a reaction $\frac{1}{2} A \to 2 B$ , rate of disappearance of ‘A' is related to the rate of appearance of ‘B’ by the expression:

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$- \frac{d [A]}{dt} = \frac{1}{2} \frac{d [B]}{dt}$

$- \frac{d [A]}{dt} = \frac{1}{4} \frac{d [B]}{dt}$

$- \frac{d [A]}{dt} = \frac{d [B]}{dt}$

$- \frac{d [A]}{dt} = 4 \frac{d [B]}{dt}$

answer is B.

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Detailed Solution

$\begin{array}{l} \frac{1}{2} A \to 2 B \\ \frac{- 2 d [A]}{dt} = + \frac{d [B]}{2 dt} \\ \frac{- d [A]}{dt} = \frac{1}{4} \frac{d [B]}{dt} \end{array}$

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