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For a reaction $\frac{1}{2} A ⟶ 2 B$ rate of disappea-rance of A is related to rate of appearance of B by the expression

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$\frac{- d [A]}{dt} = 4 \frac{d [B]}{dt}$

$\frac{- d [A]}{dt} = \frac{1}{2} \frac{d [B]}{dt}$

$\frac{- d [A]}{dt} = \frac{1}{4} \frac{d [B]}{dt}$

$\frac{- d [A]}{dt} = \frac{d [B]}{dt}$

answer is C.

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Detailed Solution

$- \frac{1}{1 / 2} \frac{d}{dt} [A] = + \frac{1}{2} \frac{d}{dt} [B] - \frac{d}{dt} [A] = \frac{1}{4} \frac{d}{dt} [B]$

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