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For a reaction $2 A + B \to$ Product rate low is $- \frac{d [A]}{d t} = k [A]$ at a time when $t = \frac{1}{k},$ concentration of
the reactant is : $(C_{0} = initial concentration)$

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$\frac{C_{0}}{C}$

$C_{0} e$

$\frac{C_{0}}{e^{2}}$

$\frac{1}{C_{0}}$

answer is A.

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Detailed Solution

$[A]_{t} = [A]_{0} e^{- k t} = \frac{C_{0}}{e}$

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