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For a reaction $4 M (s) + {nO}_{2} (g) \to 2 M_{2} O_{n} (s),$ the free energy change is plotted as a function of temperature. The temperature below which the oxide is stable could be inferred fromt the plot as the point at which:

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the slope change from positive to zero

the slope change from negative to positive

the free energy change shows a change from negative to positive value

the slope change from positive to negative

answer is D.

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Detailed Solution

If the $∆ G$ for the formation of oxide is negative then the oxide is stable more negative the $∆ G$ more is stability of oxide

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