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For a reaction $A (g) ⇌ B (g)$ at equilibrium, the partial pressure of B is found to be one fourth of the partial pressure of A. The value of $Δ G^{\circ}$ the reaction $A ⇌ B$ is:

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RT log 4

-RT log 4

RT In 4

-RT In 4

answer is A.

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Detailed Solution

The equilibrium constant is;

$K_{P}^{\circ} = \frac{1}{4}; Δ G^{\circ} = - R T \ln K_{P}^{\circ}$

Thus, option A is correct

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