For a reaction NH4COONH2(S)⇌ 2NH3(g)+CO2(g), the equilibrium pressure is 3 atm. Kp for the reaction will be_______

NH4C xOONH2(S)⇌ 2N 2xH3(g)+C xO2(g)3x=3 atmx=1 atmKP=PNH32×PCO2=(2)2×1=4

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For a reaction ${NH}_{4} COON H_{2 (S)} \overset{}{⇌} 2 {NH}_{3 (g)} + {CO}_{2 (g)},$ the equilibrium pressure is 3 atm. Kp for the reaction will be_______

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answer is 4.

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Detailed Solution

$N H_{4} \underset{\begin{array}{l} x \end{array}}{C} OON H_{2 (S)} ⇌_{}^{} 2 \underset{\begin{array}{l} 2 x \end{array}}{N} H_{3} (g) + \underset{\begin{array}{l} x \end{array}}{C} O_{2} (g)$

$3 x = 3 atm$

$x = 1 atm$

$K_{P} = {PNH}_{3}^{2} \times {PCO}_{2} = {(2)}^{2} \times 1 = 4$

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