For a real gas having $a = 4.105 atm - L^{2} / {mol}^{2}$ $b = \frac{1}{5.4} L / mole$ . If it is at an initial temperature of 300 K, then which of the following process can cause liquifaction of the gas?

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Adiabatic decrease of pressure

Isothermally increase of pressure

both (b) and (c)

Isothermally decrease of pressure

answer is C.

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Detailed Solution

The value of critical temperature,

$T_{C} = \frac{8 \times 4.105 \times 54}{27 \times 0.0821} = 80 K$
So, T = 300 K must be brought down to 80 K, which is not possible in isothermal process.

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