For a satellite escape velocity is 11 km/s. If the satellite is launched at an angle of $60^{0}$ with the vertical, then escape velocity will be

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11 km/s

$11 \sqrt{3}$ km/s

$\frac{11}{\sqrt{3}} k m / s$

33 km/s

answer is A.

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Detailed Solution

Escape velocity does not depend upon the angle of projection.

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