For a satellite moving in an orbit around the earth, the ratio of kinetic energy to the magnitude of  potential energy is

The kinetic energy of a satellite moving in an orbit around the earth is given by
$\text{K=}\frac{1}{2}{\mathrm{mv}}^2=\frac{1}{2}\mathrm{m}\left(\frac{\mathrm{GM}}{\mathrm{r}}\right)$
or $=\frac{\mathrm{GMm}}{2\mathrm{r}}$……….(1)
The potential energy of satellite and earth system
$\mathrm{U}=\frac{\mathrm{GMm}}{\mathrm{r}}$………….(2)
where r is the distance of the satellite from the centre of the earth
$\frac{\mathrm{K}}{\mathrm{U}}=\frac{\mathrm{GMm}/2\mathrm{r}}{\mathrm{GMm}/\mathrm{r}}=\frac{1}{2}$