For a series LCR circuit, I vs $ω$ curve is shown:
(a) To the left of $ω_{r}$ , the circuit is mainly capacitive.
(b) To the left of $ω_{r}$ , the circuit is mainly inductive.
(c) At $ω_{r}$ , impedance of the circuit is equal to the resistance of the circuit.
(d) At $ω_{r}$ , impedance of the circuit is 0 .
Choose the most appropriate answer from the options given below :

see full answer

Start JEE / NEET / Foundation preparation at rupees 99/day !!

21% of IItians & 23% of AIIMS delhi doctors are from Sri Chaitanya institute !!

An Intiative by Sri Chaitanya

(a) and (c) only

(a) and (d) only

(b) and (d) only

(b) and (c) only

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

at $ω_{r}, X_{C} = X_{L}$
$\Rightarrow \frac{1}{ω_{r} C} = ω_{r} L$
So if $ω < ω_{r}$ then x_C will increase and X_L will decrease.
Hence to left of $ω_{r}$ circuit is capacitive
$Z = \sqrt{R^{2} + {(X_{C} - X_{L})}^{2}}$
at $ω_{r}, Z = \sqrt{R^{2} + O^{2}} = R$