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For a transistor, the current gain of the common base configuration is 0.9. If the transistor is in the common-emitter configuration and the base current changes by 6 mA, then the change in collector current is

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20 mA

54 mA

4 mA

6 mA

answer is D.

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Detailed Solution

$\begin{array}{l} α = 0.9; β = \frac{α}{1 - α} = \frac{0.9}{1 - 0.9} = \frac{0.9}{0.1} = 9 \\ β = \frac{{ΔI}_{C}}{{ΔI}_{B}} \Rightarrow {ΔI}_{C} = β \times {ΔI}_{B} = 9 \times 6 mA = 54 mA \end{array}$

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