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Q.

For a transparent medium, relative permeability and permittivity, $μ_{r}$ and $\in_{r}$ are 1.0 and 1.44 respectively. The velocity of light in this medium would be,

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a

$2.08 \times 10^{8} m / s$

b

$3 \times 10^{8} m / s$

c

$2.5 \times 10^{8} m / s$

d

$4.32 \times 10^{8} m / s$

answer is B.

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Detailed Solution

$v = \frac{1}{\sqrt{μ \in}} = \frac{c}{\sqrt{μ_{r} \in_{r}}} = \frac{3 \times 10^{8}}{\sqrt{1 \times 1.44}}$

$= 2.5 \times 10^{8} m / s$

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